-3t^2+36t-81=0

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Solution for -3t^2+36t-81=0 equation: 



-3t^2+36t-81=0

a = -3; b = 36; c = -81;
Δ = b2-4ac
Δ = 362-4·(-3)·(-81)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-18}{2*-3}=\frac{-54}{-6}
=+9
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+18}{2*-3}=\frac{-18}{-6}
=+3
$

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